* * * * * * * * * * * * * E-Text Exercises Week Three RES/342 celestial latitude 19, 2011 11.24 In a bumper test, tethersome fictitious characters of autos were purposely crack uped into a barrier at 5 mph, and the resulting damage (in dollars) was estimated. louvre test vehicles of each type were crashed, with the results shown below. Research head leger: Are the mean crash damages the same for these deuce-ace vehicles? Crash Damage ($) giant star   varmint   Weasel 1,600      1,290      1,090    760      1,400      2,100    880      1,390      1,830 1,950      1,850      1,250 1,220       950      1,920 Hypotheses: H0: ?1=?2=?3 Ha:At to the lowest degree one of the means is/ be different Reject the null pellet if the p-value is less than 0.05. Goliath| varment| Weasel| 1600| 1290| 1090| 760| 1400| 2100| 880| 1390| 1830| 1950| 1850| 1250| 1220| 950| 1920| One factor analysis of variance| | | | | | | | | | | | | | | | Mean| n| Std. Dev|  | | | | 1432| 1,282.0 | 5| 496.
31 | Goliath| | | | 1432| 1,376.0 | 5| 321.84 | varmint| | | | 1432| 1,638.0 | 5| 441.78 | Weasel| | | | | 1,432.0 | 15| 424.32 | suit| | | | | | | | | | | | ANOVA table| | | | | | | | ejaculate| SS| df| MS| F| p-value| | | usage| 340,360.00 | 2| 170,180.000 | 0.94| .4188| | | Error| 2,180,280.00 | 12| 181,690.000 | | | | | Total| 2,520,640.00 | 14| Â | Â | Â | | | run to the ANOVA above, the test statistic is 0.94 and the p-value is 0.4188. Since the p-value is non less than 0.05, the null surmisal is not rejected and it is conclude the 3 means ar significantly equal.If you want to take a shit a full essay, ready up it on our website:
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